Let an object be placed at some height h cm and let P and Q be two points of observation which are
at a distance 10 cm apart on a line inclined at angle 15° to the horizontal. If the angles of elevation of
the object from P and Q are 30°and 60° respectively then find h.
at a distance 10 cm apart on a line inclined at angle 15° to the horizontal. If the angles of elevation of
the object from P and Q are 30°and 60° respectively then find h.
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Consodering both the triangles,
In first triangle,
tan 30 = h/x+10
And in other triangle,
tan 60 = h/x
x = h/tan 60
Now put in equation 1,
tan 30 = h/(h/tan 60)+10
0.57=h/0.57h+10
0.325h + 5.7 = h
5.7 = 0.675h
h = 5.7/0.675
h = 8.44