Answer:

Let a planet exist whose mass and radius are one third of that on the surface of earth. calculate the acceleration due to gravity at its surface if acceleration due to gravity on Earth is ge

Explanation:

let the mass of earth be Me and radius of earth be Re.

ge=Gme/(Re)^2 --------- (1)

also

let mass of planet be M =Me/3

and radius of planet R=Re/3

g=Gm/(R)^2-------------(2)

g=GMe/3(Re/3)^2

g=GMe*9/3Re^2

g=3GMe/Re^2

divinding equation (1) by equation (2)

(ge)/(g)=GMe/(R)^2/3GMe/(Re)^2

ge/g=1/3

g=3ge

Therefore the acceleration due to gravity on the surface of planet is 3 times that of earth.