Answer:
[tex]let \: \: the \: \: breadth \: \: be \: x \\ then | \: length \: is \: 3x + 6 \\ \\ area \: of \: a \: rectangle \: \: \: (l \times b) \\ = > x \times 3x + 6 = 240cm^{2} \\ = > 3 {x}^{2} + 6 = 240cm^{2} \\ 3 {x}^{2} = 240 - 6 \\ 3 {x}^{2} = 234 \\ {x}^{2} = \frac{234}{3} = 78 \\ x = \sqrt{78} \\ x = 8.831 \\ \\ breadth = 8.831cm \\ length = (3 \times 8.831) + 6 \\ = 32.493cm[/tex]
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Answer:
[tex]let \: \: the \: \: breadth \: \: be \: x \\ then | \: length \: is \: 3x + 6 \\ \\ area \: of \: a \: rectangle \: \: \: (l \times b) \\ = > x \times 3x + 6 = 240cm^{2} \\ = > 3 {x}^{2} + 6 = 240cm^{2} \\ 3 {x}^{2} = 240 - 6 \\ 3 {x}^{2} = 234 \\ {x}^{2} = \frac{234}{3} = 78 \\ x = \sqrt{78} \\ x = 8.831 \\ \\ breadth = 8.831cm \\ length = (3 \times 8.831) + 6 \\ = 32.493cm[/tex]