Answer:

If 1 1 1 1=R, and 2 2 2 2=T, and 3 3 3 3=E, and 4 4 4 4=N, then what will 5 5 5 5=?

The Q has two pattern. Its not a perfect Q. It can be asked in exam only if Options are given. Otherwise it would become incorrect Q as it has two patterns and Q can be disputed if asked without options.

First pattern:

Sum of every digit- write it down in word.

5+5+5+5=20 write it in word

Twenty. So if u follow this pattern answer is "Y"

2nd pattern:

Find out the "Digital Root"

1+1+1+1=4. 4 is the Digital Root. Write it down in word - FOUR

2+2+2+2=8. 8 is digital root. EIGHT

3+3+3+3=12. 12=1+2=3. THREE

4+4+4+4=16. 16=7. SEVEN

HENCE

5+5+5+5=20. 20=2+0=2. TWO

As per 2nd pattern answer is "O"

This Q cannot be asked without options.

Even if options are given and both "Y" and "O" are given, then we can dispute the Q. If options have only one of "Y" or "O"

Then Q is correct.

However…

I would choose "Y" as answer if both are in option. Bcz of another pattern.

In first pattern:

Four

Eight

Twelve

Sixteen

Twenty

The answers in every line also follow a pattern.

4---8---12---16---20

Adding 4 consecutively.

So i would choose "Y" for safe side