What volume of 63 % HNO3(wt/wt) having density 1.4 g m/L is required to prepare 200 ml of 0.7M HNO3 Solution is
1)15 ml
2)10 ml
3)20 ml
4)40 ml
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1)15 ml
2)10 ml
3)20 ml
4)40 ml
No spam answers
Wrong answers will be deleted and correct answer will be awarded brainliest.
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Given Data
Formula applied
M = density × w/w% of Solute × 10 /Gram molecular weight
Now ,
Putting the above values in the given formula
We get ,
M = 3.63× 10 ×1.4 / 63
Upon solving ,
We get
M = 14 .
As we know
M1V1 = M2V2
14 × V1 = 0.7 × 200
V1 = 0.7 × 200 / 14
= 7× 200 / 10 × 14
= 200 / 10 × 2
V1 = 10 ml
Answer
Option 2) 10 ml