koi to bta do answer.....
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Ask - Ok let me tell u clearly..the question is " Product of number formed * sum of its digits".
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Answers & Comments
Let the tens digit be x.
Given that unit's digit exceeds its tens digit by 2.
Then the units digits = x + 2.
Hence, the original number = 10x + (x + 2)
= > 10x + x + 2
= > 11x + 2 ----- (1)
(i)
Given that product of its digit and sum of its digit is equal to 144.
= > (11x + 2)(x + x + 2) = 144
= > (11x + 2)(2x + 2) = 144
= > 22x^2 + 22x + 4x + 4 = 144
= > 22x^2 + 26x + 4 = 144
= > 22x^2 + 26x = 140
= > 22x^2 + 26x - 140 = 0
= > 11x^2 + 13x - 70 = 0
= > 11x^2 - 22x + 35x - 70 = 0
= > 11x(x - 2) + 35(x - 2) = 0
= > (x - 2)(11x + 35) = 0
= > x = 2, x = -35/11{x cannot be negative].
= > x = 2.
Now,
Substitute in (1), we get
= > 11x + 2
= > 11(2) + 2
= > 24
Therefore, the number is 24.
Hope this helps!