Verified answer

Explanation:

(a) a = ++a + a--/ ++a + --a; when a = 2

Here, we can break down the expression as follows:

a = ++a + a--/ ++a + --a;

a = 3 + 2/4 + 2;

a = 3 + 0 + 2;

a = 5;

Therefore, the output of the expression is 5.

(b) i *= j++ % j--/k *10; when i=2,j=4,k=3

Here, we can break down the expression as follows:

i *= j++ % j--/k *10;

i *= 4 % 4/3 * 10;

i *= 4 % 1 * 10;

i *= 0 * 10;

i = 0;

Therefore, the output of the expression is 0.

Explanation:

a = ++a + a--/++a + --a; when a = 2.

Step 1: ++a (Pre-increment operation, so a becomes 3)

Step 2: a-- (Post-decrement operation, a is still 3, but it will be 2 next time)

Step 3: ++a (Pre-increment operation, a becomes 3 again)

Step 4: a-- (Post-decrement operation, a is still 3, but it will be 2 next time)

Step 5: --a (Pre-decrement operation, a becomes 2)

Step 6: Calculation from left to right:

++a = 3

a-- = 3

++a = 4

3/4 = 0 (integer division)

0 + 4 = 4

--a = 3

4 + 3 = 7

Therefore, the output of the expression is 7.

ii *= j++ % j--/k *10; when i=2,j=4,k=3

Step 1: j++ (Post-increment operation, j becomes 5, but it will be 4 next time)

Step 2: j-- (Post-decrement operation, j is still 5, but it will be 4 next time)

Step 3: j++ % j-- (4%5=4)

Step 4: k10 (310=30)

Step 5: j++ % j--/k *10 (4/30=0)

Step 6: i *= j++ % j--/k 10 (i=2, 20=0)

Therefore, the output of the expression is 0.