Answer:
i think it is correct
Step-by-step explanation:
I = ∫2x/x²+3x+2 . dx
I can help you with that integral.
First, we can factor the denominator of the integrand as follows:
x² + 3x + 2 = (x + 2)(x + 1)
Then, we can rewrite the integrand as:
2x / (x + 2)(x + 1)
We can then use partial fraction decomposition to rewrite the integrand as:
A / (x + 2) + B / (x + 1)
where A and B are constants that we need to solve for.
Multiplying both sides by (x + 2)(x + 1), we get:
2x = A(x + 1) + B(x + 2)
Expanding and equating coefficients of x on both sides, we get:
2 = A + B
Equating constant terms on both sides, we get:
0 = A + 2B
Solving these equations simultaneously, we get:
A = -2 and B = 4
Therefore, the integral becomes:
∫ [ -2 / (x+2) ] dx + ∫ [ 4 / (x+1) ] dx
Integrating each term separately, we get:
-2 ln|x+2| + 4 ln|x+1| + C
where C is the constant of integration.
So the final answer is:
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Answers & Comments
Answer:
i think it is correct
Step-by-step explanation:
Answer:
Step-by-step explanation:
I = ∫2x/x²+3x+2 . dx
I can help you with that integral.
First, we can factor the denominator of the integrand as follows:
x² + 3x + 2 = (x + 2)(x + 1)
Then, we can rewrite the integrand as:
2x / (x + 2)(x + 1)
We can then use partial fraction decomposition to rewrite the integrand as:
A / (x + 2) + B / (x + 1)
where A and B are constants that we need to solve for.
Multiplying both sides by (x + 2)(x + 1), we get:
2x = A(x + 1) + B(x + 2)
Expanding and equating coefficients of x on both sides, we get:
2 = A + B
Equating constant terms on both sides, we get:
0 = A + 2B
Solving these equations simultaneously, we get:
A = -2 and B = 4
Therefore, the integral becomes:
∫ [ -2 / (x+2) ] dx + ∫ [ 4 / (x+1) ] dx
Integrating each term separately, we get:
-2 ln|x+2| + 4 ln|x+1| + C
where C is the constant of integration.
So the final answer is:
-2 ln|x+2| + 4 ln|x+1| + C