Explanation:

Joseph jogs from one end A to the other end B of a straight 300 m

road in 2 minutes 30 seconds and then turns around and jogs 100 m

back to point C in another 1 minute. What are Joseph's average speeds

and velocities in jogging (a) from A to B and (b) from A to C ?

Answer:

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=

Timetaken

Distance covered

=

150

300

=2 m/sec

Average velocity=

Timetaken

Displacement

=

150

300

=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=

Timetaken

Distance covered

=

210

400

=1.90 m/sec

Average velocity=

Timetaken

Displacement

=

210

200

=0.95 m/sec