Given:

Jimmy has 50¢ in his pocket amounting P 90.00.

His 10¢ coins  amounting to P 12.00

To find:

How many more 50¢ coins than 10¢ coins does  Jimmy have?​

Solution:

We know,

So,

50 ¢ = 50 × 0.01 ₱ = 0.5 ₱

10 ¢ = 10 × 0.01 ₱ = 0.10 ₱

The total amount of 50 ¢ or 0.5 ₱ coins = ₱ 90.00

∴ No. of 50 ¢ or 0.5 ₱ coins =

The total amount of 10 ¢ or 0.1 ₱ coins = ₱ 12.00

∴ No. of 10 ¢ or 0.1 ₱ coins =

∴ The difference between no. of 50 ¢ and 10 ¢ = 180 - 120 = 60

Thus, Jimmy has 60 more 50 ¢ coins than 10 ¢ in his pocket.

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