Jeffrey goes to National Book Store to buy Novel books for 250 pesos and USB for 490
pesos. If he has a budget of 2450, write an inequality to describe the possible number of Novel books and USBs that Jeffrey can buy. If Jeffrey buys 4 Novel books, what is the
maximum number of USBs he can buy?
pesos. If he has a budget of 2450, write an inequality to describe the possible number of Novel books and USBs that Jeffrey can buy. If Jeffrey buys 4 Novel books, what is the
maximum number of USBs he can buy?
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Answer:
If Jeffrey buys 4 novel books therefore he can only buy 2 USB's
NB=250Php
USB=490Php
P250.00*4 = P1,000(total cost of novel books)
P2,450.00(Budget) - P1,000(total cost of novel books) = P1,450.00(money left)
P1,450.00(money left) / 490(cost of USB) = 2.959183673469388(number of USB)
P490.00*2= P980.00(total cost of USB)
P1,450.00(money left) - P980.00(total cost of USB) = P470.00(money left)
Total USB: 2
Total NB: 4
Total USB Amount: P980.00
Total NB Amount: P1,000.00
Total Money Left: P470.00
Answer:
250B + 490U ≤ 2450
two usbs.
Step-by-step explanation:
Inequality:
where b = books, u = usbs
250B + 490U ≤ 2450
If given the number of novel books, which is 4,
(250)(4) + 490U = 2450
1000 + 490U = 2450
490U = 2450 - 1000
490U = 1,450
U = 2.9
Therefore, the maximum number of USBs he can buy are two.