Answer:
Step-by-step explanation:
The given details are,
BL⊥AC,DM⊥AC and EN⊥AC
AC=18cm,AM=14cm,AN=6cm,BL=4Cm,DM=12cm,EN=9cm
MC=AC−AM=18−14=4cm
MN=AM−AN=14−6=8cm
By using the formula,
Area (pent.ABCDE) =area(△AEN)+area(△DMC)+area(△ABC)+area(Trap.DMNE)
Area of trapezium =1/2×(sum of parallel sides)
Area(△AEN)= 1/2(an)(en)= 1/2×6×9= 27cm²--(I)
Area(△DMC)= 1/2mc× dm= 24cm²---------(ii)
Area(△ABC= 1/2 ×18×4= 36cm²-------(iii)
Area(Trap.DMNE)= 1/2×(DM+EN)× MN= 84cm²----(iv)
area is Pentagon= (I)+(ii)+(iii)+(iv)
= 171cm²
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Answers & Comments
Answer:
171cm²
Step-by-step explanation:
The given details are,
BL⊥AC,DM⊥AC and EN⊥AC
AC=18cm,AM=14cm,AN=6cm,BL=4Cm,DM=12cm,EN=9cm
MC=AC−AM=18−14=4cm
MN=AM−AN=14−6=8cm
By using the formula,
Area (pent.ABCDE) =area(△AEN)+area(△DMC)+area(△ABC)+area(Trap.DMNE)
Area of trapezium =1/2×(sum of parallel sides)
Area(△AEN)= 1/2(an)(en)= 1/2×6×9= 27cm²--(I)
Area(△DMC)= 1/2mc× dm= 24cm²---------(ii)
Area(△ABC= 1/2 ×18×4= 36cm²-------(iii)
Area(Trap.DMNE)= 1/2×(DM+EN)× MN= 84cm²----(iv)
area is Pentagon= (I)+(ii)+(iii)+(iv)
= 171cm²
pls pls mark me as brainliest for your perfect correct answer.....!!!!!!