It cost rupees 2200 to paint the inner curved surface of the cylinder kal vessels 10 mm deep if the cost of painting is at the rate of 20 m m square find 1 inner curved surface area of vessel 2 bradius of the base 3 Capacity city of the base
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(i) Cost of painting 1m2 area =Rs.20
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m(iii) Volume of vessel
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m(iii) Volume of vessel =πr2h=722×1.75×1.75×10
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m(iii) Volume of vessel =πr2h=722×1.75×1.75×10=96.25m3
(i) Cost of painting 1m2 area =Rs.20⇒Rs.20 is cost painting 1 m2 area⇒Rs.2200 is cost of painting =202200m2=110m2 area(ii) Let radius =r1, h=10m, SA=2πrh=110⇒r=22×2×10110×7=47=1.75m(iii) Volume of vessel =πr2h=722×1.75×1.75×10=96.25m3=96250 litres