Answer:
It's wrong
Step-by-step explanation:
as you're doing splitting the middle term, the terms have to sum up.
Once you split it has to be 3 [tex]x^{2}[/tex] + 3x - 4x + 4 and not 3 [tex]x^{2}[/tex] - 3x + 4x + 4
Then you can do the rest.
sis. your answer is wrong
You have to take +3x - 4x
Because +3x - 4x = - x (which is required number)
To solve
[tex] \large{ {3x}^{2} - x - 4 } \\ \large{ {3x}^{2} \red{+ 3x - 4x} - 4} \\ \large{3x(x + 1) - 4(x + 1)} \\ \large{(3x - 4)(x + 1)}[/tex]
sis i think aapko factorise wale question me problem ho rahi hi because three times you have sent same question but all the time i found it incorrect
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
It's wrong
Step-by-step explanation:
as you're doing splitting the middle term, the terms have to sum up.
Once you split it has to be 3 [tex]x^{2}[/tex] + 3x - 4x + 4 and not 3 [tex]x^{2}[/tex] - 3x + 4x + 4
Then you can do the rest.
Answer:
sis. your answer is wrong
You have to take +3x - 4x
Because +3x - 4x = - x (which is required number)
Step-by-step explanation:
To solve
[tex] \large{ {3x}^{2} - x - 4 } \\ \large{ {3x}^{2} \red{+ 3x - 4x} - 4} \\ \large{3x(x + 1) - 4(x + 1)} \\ \large{(3x - 4)(x + 1)}[/tex]
sis i think aapko factorise wale question me problem ho rahi hi because three times you have sent same question but all the time i found it incorrect