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GANESHBA
@GANESHBA
September 2021
1
9
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is there any body to slove it . .?& capacity to explain it?..
Now show ur talent,,,,;;;!!!!!
Answers & Comments
siddhartharao77
Verified answer
The word Mahabharat contains 10 letters.
It contains 4A's, 2H's, 1B, 1T, 1M, 1R.
The required number of ways = 10!/4!2!1!1!1!
= 10!/4!2!.
(1) Given that B and T are never together.
Consider That as 1-unit(10 - 1)! = 9!.
= 9!/4!2!1!1!
= 9!/4!2!.
Therefore the required number of ways = 10!/4!2! - 9!/4!2!
= 3265920/48
=
68040.
(2) M,A,T,H occurs at first four places.:
Observe this carefully:
- - - -
M A T H ---------- Now, these four letters can be arranged themselves in4! ways.
The remaining letters can be arranged in = A,B,H,A,R,A
= 6!/3! ----- Here 3! = (3 A's)
Therefore the total number of ways = 6!/3! * 4!
= 4 * 5 * 6 * 4 * 3 * 2 * 1
=
2880.
Hope this helps!
0 votes
Thanks 4
siddhartharao77
Waiting for ur answer Sis.. :-):-):-)
HridayAg0102
Nice ...
siddhartharao77
Thank for genius...:-)
siddhartharao77
Thanks @Hriday
HridayAg0102
✌☺
GANESHBA
grt great u are real Hero sir i salute....sir ...... thanks thanks
siddhartharao77
Thank you..
GANESHBA
can i sent one more question....
siddhartharao77
Thank you
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Answers & Comments
Verified answer
The word Mahabharat contains 10 letters.It contains 4A's, 2H's, 1B, 1T, 1M, 1R.
The required number of ways = 10!/4!2!1!1!1!
= 10!/4!2!.
(1) Given that B and T are never together.
Consider That as 1-unit(10 - 1)! = 9!.
= 9!/4!2!1!1!
= 9!/4!2!.
Therefore the required number of ways = 10!/4!2! - 9!/4!2!
= 3265920/48
= 68040.
(2) M,A,T,H occurs at first four places.:
Observe this carefully:
- - - -
M A T H ---------- Now, these four letters can be arranged themselves in4! ways.
The remaining letters can be arranged in = A,B,H,A,R,A
= 6!/3! ----- Here 3! = (3 A's)
Therefore the total number of ways = 6!/3! * 4!
= 4 * 5 * 6 * 4 * 3 * 2 * 1
= 2880.
Hope this helps!