Answer:
Let S
m and S n
be the sum of the first m and first n terms of the AP respectively. Let, a be the first term and d be a common difference
S n
S m
=
m
2
⇒
n
[2a+(n−1)d]
[2a+(m−1)d]
2a+(n−1)d
2a+(m−1)d
⇒n[2a+(m−1)d]=m[2a+(n−1)d]
⇒2an+mnd−nd+2am+mnd−nd
⇒md−nd=2am−2an
⇒(m−n)d=2a(m−n)
⇒d=2a
Now, the ratio of mth and nth terms is
a
a+(n−1)d
a+(m−1)d
a+(n−1)2a
a+(m−1)2a
a(1+2n−2)
a(1+2m−2)
2n−1
2m−1
Thus, ratio of its mth and nth terms is 2m−1:2n−1
Iron nails lose their shiny appearance because an insoluble layer of copper is formed on the nails, Meanwhile, the solution,CuSO4 loses its blue color because of the formation of FeSO4.
Fe + CuSO4 → Cu + FeSO4
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Answers & Comments
Answer:
Let S
m and S n
be the sum of the first m and first n terms of the AP respectively. Let, a be the first term and d be a common difference
S n
S m
=
m
2
⇒
2
n
[2a+(n−1)d]
2
m
[2a+(m−1)d]
=
n
2
m
2
⇒
2a+(n−1)d
2a+(m−1)d
=
n
m
⇒n[2a+(m−1)d]=m[2a+(n−1)d]
⇒2an+mnd−nd+2am+mnd−nd
⇒md−nd=2am−2an
⇒(m−n)d=2a(m−n)
⇒d=2a
Now, the ratio of mth and nth terms is
a
n
a
m
=
a+(n−1)d
a+(m−1)d
=
a+(n−1)2a
a+(m−1)2a
=
a(1+2n−2)
a(1+2m−2)
=
2n−1
2m−1
Thus, ratio of its mth and nth terms is 2m−1:2n−1
Answer:
Iron nails lose their shiny appearance because an insoluble layer of copper is formed on the nails, Meanwhile, the solution,CuSO4 loses its blue color because of the formation of FeSO4.
Fe + CuSO4 → Cu + FeSO4