Let t=sinx−cosxt=sinx−cosx , dx=dtsinx+cosxdx=dtsinx+cosx
x→π2⟹t=(sinx−cosx)→1x→π2⟹t=(sinx−cosx)→1x→0⟹t=(sinx−cosx)→−1x→0⟹t=(sinx−cosx)→−12–√∫1−111−t2−−−−−√dt=2–√[sin−1t]1−1=2–√[π2−(−π2)]=2–√π2∫−1111−t2dt=2[sin−1t]−11=2[π2−(−π2)]=2π hope it is use full
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Let t=sinx−cosxt=sinx−cosx , dx=dtsinx+cosxdx=dtsinx+cosx
x→π2⟹t=(sinx−cosx)→1x→π2⟹t=(sinx−cosx)→1 x→0⟹t=(sinx−cosx)→−1x→0⟹t=(sinx−cosx)→−1 2–√∫1−111−t2−−−−−√dt=2–√[sin−1t]1−1=2–√[π2−(−π2)]=2–√π2∫−1111−t2dt=2[sin−1t]−11=2[π2−(−π2)]=2πhope it is use full