Verified answer

Step-by-step explanation:

In △ADC and △BAC

∠ADC=∠BAC (Given)

∠C is Common

Your answer

∴ by AA Criterion of Similarity, △ADC ∼ △BAC

⇒BAAD=ACDC=BBCAC

⇒ACDC=BCAC

∴ CA2=CB.CD

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Step-by-step explanation:

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