We know that if a line through one of the vertex of a triangle divides the opposite side in the ratio of the other two sides, the line bisects the angle at the vertex.
So in the given equation,
ACAB=CDBD
⇒AD bisects ∠A.
∠A=180∘−(70∘+50∘) (Sum of angles of a triangle =180∘)
We know that if a line through one of the vertex of a triangle divides the opposite side in the ratio of the other two sides, the line bisects the angle at the vertex.
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Answer:
Solution

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We know that if a line through one of the vertex of a triangle divides the opposite side in the ratio of the other two sides, the line bisects the angle at the vertex.
So in the given equation,
ACAB=CDBD
⇒AD bisects ∠A.
∠A=180∘−(70∘+50∘) (Sum of angles of a triangle =180∘)
∴∠BAD=2∠A=260∘=30∘
Step-by-step explanation:
hope it helps
Step-by-step explanation:
We know that if a line through one of the vertex of a triangle divides the opposite side in the ratio of the other two sides, the line bisects the angle at the vertex.
So in the given equation,
ACAB=CDBD
→ AD bisects ZA.
ZA=180°-(700+50°) (Sum of angles of a
triangle =180°)
..<BAD=2<A=260⁰=30°