A =  P(1+r∕100)^t

Where,

P is Principal (or sum)

t is time (in years)

A is the amount, person will get after time t

r is rate of interest per annum

Here,

A=2395.80

P=1800

t=?

r=10%

apply the formula,

2395.80=1800(1+10/100)^t

t=3 years

Answer:

Time = 3 yrs

Step-by-step explanation:

Question: In what time will the amount of ₹ 1800 at 10% compound interest become ₹ 2395.80.​

Formula used:

[tex]\sf{\implies{Amount = P(1+\dfrac{r}{n})^{nt}}}[/tex]

P = Principle, R = Rate of interest, T = Time

Calculations:

P = ₹ 1,800, R = 10%, T = ?

[tex]\sf{\implies{2395.8 = 1800(1+\dfrac{10}{100})^{t}}}[/tex]

[tex]\sf{\implies{2395.8 = 1800(1+0.10)^{t}}}[/tex]

[tex]\sf{\implies{2395.8 = 1800(1.10)^{t}}}[/tex]

[tex]\sf{\implies{\dfrac{2395.8}{1800} = (1.10)^{t}}}[/tex]

[tex]\sf{\implies{1.331 = (1.10)^{t}}}[/tex]

[tex]\sf{\implies{(1.10)^3 = (1.10)^{t}}}[/tex]

[tex]\sf{\implies{t = 3\:yrs}}[/tex]

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