Answer:
1. QE
Explanation:
We need to convert the equation into its standard form.
6=7x \ (4x)6=7x (4x)
6=28x^{2}6=28x
2
\begin{gathered}28x^{2}=6\\\end{gathered}
28x
=6
28x^{2}-6=028x
−6=0
2. QE
It is already on its standard form and it is equated to 0.
3. QE
Using the FOIL Method, convert the factored form into standard form.
\begin{gathered}(a-8)(a+5)=14\\a^{2} +5a-8a-40=14\\a^{2} -3a-40-14=0\\a^{2} -3a-54=0\end{gathered}
(a−8)(a+5)=14
a
+5a−8a−40=14
−3a−40−14=0
−3a−54=0
4. NQE
Transpose 10 to the other side.
\begin{gathered}5x+5y=10\\5x+5y-10=0\end{gathered}
5x+5y=10
5x+5y−10=0
5. QE
\begin{gathered}7=8m^{2} -2m\\8m^{2} -2m-7=0\end{gathered}
7=8m
−2m
8m
−2m−7=0
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Answers & Comments
Answer:
1. QE
Explanation:
We need to convert the equation into its standard form.
6=7x \ (4x)6=7x (4x)
6=28x^{2}6=28x
2
\begin{gathered}28x^{2}=6\\\end{gathered}
28x
2
=6
28x^{2}-6=028x
2
−6=0
2. QE
Explanation:
It is already on its standard form and it is equated to 0.
3. QE
Explanation:
Using the FOIL Method, convert the factored form into standard form.
\begin{gathered}(a-8)(a+5)=14\\a^{2} +5a-8a-40=14\\a^{2} -3a-40-14=0\\a^{2} -3a-54=0\end{gathered}
(a−8)(a+5)=14
a
2
+5a−8a−40=14
a
2
−3a−40−14=0
a
2
−3a−54=0
4. NQE
Explanation:
Transpose 10 to the other side.
\begin{gathered}5x+5y=10\\5x+5y-10=0\end{gathered}
5x+5y=10
5x+5y−10=0
5. QE
Explanation:
\begin{gathered}7=8m^{2} -2m\\8m^{2} -2m-7=0\end{gathered}
7=8m
2
−2m
8m
2
−2m−7=0