Verified answer

Answer:

Given:-

In ∆ADB and ∆CBD,

AB=CD

AB||CD

Answer:-

.°.Angle 1=Angle 2[Alternate interior angles]

Also,BD=BD[Common sides]

.°.∆ADB~∆CBD[SAS Rule]

=>Angle 3 =Angle 4[By CPCT]

.°.AD||BC[One pair of alternate interior angles are equal]

So,both the pairs of opposite angles are parralel.Thus,ABCD is a parallelogram.

Additional imformation:-

•Always draw the the image while practising

•Never forget to write how you got an angle

Step-by-step explanation:

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Answer:

Given:-

In ∆ADB and ∆CBD,

AB=CD

AB||CD

Answer:-

.°.Angle 1=Angle 2[Alternate interior angles]

Also,BD=BD[Common sides]

.°.∆ADB~∆CBD[SAS Rule]

=>Angle 3 =Angle 4[By CPCT]

.°.AD||BC[One pair of alternate interior angles are equal]

So,both the pairs of opposite angles are parralel.Thus,ABCD is a parallelogram.

Additional imformation:-

•Always draw the the image while practising

•Never forget to write how you got an angle

Step-by-step explanation:

I HOPE IT HELPS