In the reaction, PCl_5(g)⇌PCl_3(g)+Cl_2(g) , the amounts of PCl_5, PCl_3 and Cl_2 are 2 mole each at equilibrium and the total pressure is 3 atmosphere. The equilibrium constant, K_p is
Answer must be "1 atm"
Answer must be "1 atm"
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EXPLANATION.
PCI₅(g) ⇄ PCI₃(g) + CI₂(g).
The amount of PCI₅ & PCI₃ & CI₂ = 2 mole each at equilibrium.
Total pressure = 3 atm.
As we know that,
PCI₅(g) ⇄ PCI₃(g) + CI₂(g).
2 2 2 at t = equilibrium.
Expression of K(p) is.
Total number of the moles = 2 + 2 + 2 = 6 moles.
MORE INFORMATION.
Summary various homogenous equilibrium.
(1) = H₂ + I₂ ⇄ 2HI.
(2) = N₂ + O₂⇄ 2NO
⇒ Δn = 0.
⇒ ΔH = +QK cal (endothermic) K(p) = Kc.
⇒ Kc = 4x²/(a - x)(b - x)
⇒ K(p) = 4x²/(a - x)(b - x).
Helping factors = to obtain ↑ NO & HI.
⇒ (a) = high temperature.
⇒ (b) = [N₂] & [O₂] ↑.
⇒ (c) = p → no effect.