in the given figure if o is the centre of a circle. AB is a chord and the tangent AC at A makes an angle 65 degree with AB, then find the Angle AOB
Answers & Comments
MilitheQUORAN
Angle AOC = 90° (Radius is perpendicular at point of contact with tangent) angle BAC = 65° therefore , angleOAB = 90°- 65° = 25° Now in triangle AOB , AO = BO (radius) therefore angle OAB = angle OBA therefore angle AOB = 180°- (25°× 2)= 130°
Answers & Comments
angle BAC = 65°
therefore , angleOAB = 90°- 65° = 25°
Now in triangle AOB ,
AO = BO (radius)
therefore angle OAB = angle OBA
therefore angle AOB = 180°- (25°× 2)= 130°
Hope it helps!