As AE || BF, z+y=180(Interior Angle) z+30=180 z=150°
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Simar111
Since A.C. is parralel to BD and AN is a transversal we have angle cab + angle dba = 180 ( co interior angles are supplementary theroem) therefore 115+x=180 x=180-115=65
now we have dbg is a straight line therefore x+y+angle fbg = 180 (linear pair) 65+y+85=180 y+150=180 y=30
since ae is parralel to bg and ab is a transversal therefore z+y=180(cointerior angles are supplementary) z+30=180 z=150
Answers & Comments
115°+x=180° (Interior Angle)
Therefore x=65°.
x+y+86=180(Supplementary angle)
y+65+85=180
y+150=180
y=30°
As AE || BF,
z+y=180(Interior Angle)
z+30=180
z=150°
angle cab + angle dba = 180 ( co interior angles are supplementary theroem)
therefore
115+x=180
x=180-115=65
now we have dbg is a straight line therefore
x+y+angle fbg = 180 (linear pair)
65+y+85=180
y+150=180
y=30
since ae is parralel to bg and ab is a transversal
therefore
z+y=180(cointerior angles are supplementary)
z+30=180
z=150