Answer:
B.
=180degree - 110degree [linear pair}
= 70degree
In triangle....
=70degree+40degree+ Y = 180degree {sum of triangle property}
=90degree +Y = 180degree
Y= {180-90}degree
Y= 90degree
Z = 40degree {Alt. interior angle}
X+Y+Z=180Degree
X+ 90 DEGREE+40 DEGREE=180 {linear pair}
X=180-130
X=50degree
Step-by-step explanation:
thx....
b) l||m
40°=z(alternate interior angle)
110°=y+z(corresponding angles)
110°=y+40°
y=110°-40°=70°
40°+x+y=180°(supplementary angles)
40°+x+70°=180°
x=180°-110°=70°
c)y-80°=x(alternate interior angles)
y+x=180°(linear pair)
y+y-80°=180°
2y=180°+80°
2y=260°
y=260°/2=130°
y-80=x
130°-80°=x
50°=x
y-80°+z=180°(linear pair)
50°+z=180°
z=180°-50°=130°
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Answers & Comments
Answer:
B.
=180degree - 110degree [linear pair}
= 70degree
In triangle....
=70degree+40degree+ Y = 180degree {sum of triangle property}
=90degree +Y = 180degree
Y= {180-90}degree
Y= 90degree
Z = 40degree {Alt. interior angle}
X+Y+Z=180Degree
X+ 90 DEGREE+40 DEGREE=180 {linear pair}
X=180-130
X=50degree
Step-by-step explanation:
thx....
Answer:
b) l||m
40°=z(alternate interior angle)
110°=y+z(corresponding angles)
110°=y+40°
y=110°-40°=70°
40°+x+y=180°(supplementary angles)
40°+x+70°=180°
x=180°-110°=70°
c)y-80°=x(alternate interior angles)
y+x=180°(linear pair)
y+y-80°=180°
2y=180°+80°
2y=260°
y=260°/2=130°
y-80=x
130°-80°=x
50°=x
y-80°+z=180°(linear pair)
50°+z=180°
z=180°-50°=130°