Answer:
∠Q=110
∠RSP+∠RQP=180
(since PQRS is a cyclic quadrilateral)
∠RSP=180−110
=70
∠RSP+∠SPR+∠SRP=180
0
∠SRP=180−(70+60)
=180−130
∠SRP=50
=∠SRP=50
[angles in the alternate segment]
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
∠Q=110
∠RSP+∠RQP=180
(since PQRS is a cyclic quadrilateral)
∠RSP=180−110
=70
∠RSP+∠SPR+∠SRP=180
0
∠SRP=180−(70+60)
=180−130
∠SRP=50
=∠SRP=50
[angles in the alternate segment]