Answer:
Though it is not given, I am assuming on the basis of image that the Pentagon is enclosed by a circle and that O is centre of the circle.
PQ = QR
so APQR is isosceles
angle QRP
[tex]= angle \: QPR ( \frac{180 - 128}{2} )[/tex]
[tex] = \frac{52}{2} [/tex]
= 26°
now chord QR makes an angle of 26° at a point on circumference. so it will make 26*2 = 52° at centre.
now equal chords make equal angle at centre or
circumference.
angle POQ = angle QPR = angle ROS = 52°
now chord PQ makes an angle of 52° at centre, so it will make angle of 26° at circumference.
so, angle PTQ = 26°.
Again, each of the chords will make an angle of 26°.
at any point on circumference and hence on point T
also.
so angle PTS = PTQ + QTR + RTS
= 26 + 26 + 26
= 78°
Step-by-step explanation:
[tex]hope \: it \: helps \: u \: bro[/tex]
plz mark me the brainliest
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Answers & Comments
Answer:
Though it is not given, I am assuming on the basis of image that the Pentagon is enclosed by a circle and that O is centre of the circle.
PQ = QR
so APQR is isosceles
angle QRP
[tex]= angle \: QPR ( \frac{180 - 128}{2} )[/tex]
[tex] = \frac{52}{2} [/tex]
= 26°
now chord QR makes an angle of 26° at a point on circumference. so it will make 26*2 = 52° at centre.
now equal chords make equal angle at centre or
circumference.
angle POQ = angle QPR = angle ROS = 52°
now chord PQ makes an angle of 52° at centre, so it will make angle of 26° at circumference.
so, angle PTQ = 26°.
Again, each of the chords will make an angle of 26°.
at any point on circumference and hence on point T
also.
so angle PTS = PTQ + QTR + RTS
= 26 + 26 + 26
= 78°
Step-by-step explanation:
[tex]hope \: it \: helps \: u \: bro[/tex]
plz mark me the brainliest