Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameter
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)Angle ACB = 180° - ( angle ABC + angle CAB) = 180° - (40° + 90°) = 180° - 130° = 50°
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)Angle ACB = 180° - ( angle ABC + angle CAB) = 180° - (40° + 90°) = 180° - 130° = 50°Therefore,angleACB=50°
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)Angle ACB = 180° - ( angle ABC + angle CAB) = 180° - (40° + 90°) = 180° - 130° = 50°Therefore, angle ACB = 50°PLEASEMARKITASTHEBRAINLIEST!!!
Answers & Comments
angle AGE=50
Consider AC diameter
In ∆ACG
angle ACG=90
=>angle CAG=40
In ∆ACB
angle CAB=40
=>angle ACB=50
Answer: Angle ABC = 50°
Answer: Angle ABC = 50°Step-by-step explanation:
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)Angle ACB = 180° - ( angle ABC + angle CAB) = 180° - (40° + 90°) = 180° - 130° = 50°Therefore, angle ACB = 50°
Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)Angle ACB = 180° - ( angle ABC + angle CAB) = 180° - (40° + 90°) = 180° - 130° = 50°Therefore, angle ACB = 50°PLEASE MARK IT AS THE BRAINLIEST !!!