In the circuit shown below Ώ The potential difference across the 3 Ω resistor is (a) 19 V (b) 12 V (c) 1 V (d) 2 V; In the circuit shown below Ώ The potential difference across the 3 Ω resistor is (a) 19 V (b) 12 V (c) 1 V (d) 2 V
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Answer:
In this case, 2 resistances of 6 ohms and 4 ohms are connected in series. So the total resistance is given as 6+4 = 10 ohms.
The potential difference across the circuit is given as 20 V. The current in the circuit can be determined from the relation I=
R
V
=
10
20
A=2 A.
Hence, the current in the circuit is 2 ampere.
As the current is same across a serially connected circuit, the voltage across the 6 ohms resistor can be determined using the relation: V=IR.
That is, V=2A×6Ω=12 V.
Hence, the potential difference across the 6 ohms resistor is 12 V.
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SIMILAR QUESTIONS
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Three resistors 1Ω, 2Ω and 3Ω are connected to form a triangle. Across 3Ω resistor a 3V battery is connected. The current through 3Ω resistor is:
Medium