In the adjoining figure AB= AC, CP || BA and AP is the bisector of angle CAD prove that angle PAC = angle BCA and ABCD is a parallelogram This was the first question this is the second question
The diagonals AC and BD of a rhombus intersect each other at O prove that AB2+BC2+CD2+DA2=4 (OA2+OB2)
The diagonals AC and BD of a rhombus intersect each other at O prove that AB2+BC2+CD2+DA2=4 (OA2+OB2)