[tex] { \small{ \sf \rightarrow \red{area(ABCD) = area(BCD) + area(ABC)}}}[/tex]

[tex] \small{ \rightarrow\sf area(ABCD) = (\frac{1}{2} \times BC \times OD) + ( \frac{1}{2} \times AB \times CX) }[/tex]

[tex] \small \sf \rightarrow area(ABCD) = (\frac{1}{2} \times 25 \times 4) + ( \frac{1}{2} \times 24 \times 7) [/tex]

[tex]\small \sf \rightarrow area(ABCD) = (50) + ( 84) [/tex]

[tex]\small \pink{ \sf \rightarrow area(ABCD) = 134 {cm}^{2} }[/tex]

[tex] \blue{ \bigstar \: \sf{Pre-Requisite \: Knowledge}}[/tex]

[tex] \small \green{\sf \: area \: of \triangle \: = \frac{1}{2} \times base \times height}[/tex]

[tex] \\ \\ \small{ \red {\bigstar}} \small{ \pmb{ \sf{ \fcolorbox{pink}{back}{ \: \:\: \:\: \: @Saanvigrover2007 \: \:\: \:\: \:}} \red \bigstar}} \\ [/tex]

Verified answer

Answer:

134 cm²

Step-by-step explanation:

Given, AB = 24cm, BC = 25cm, CX = 7cm, DO = 4cm.

Area of quadrilateral ABCD = Area of ∆ABC + Area of ∆BCD

= 1/2 × 24 × 7 + 1/2 × 25 × 4

= 12 × 7 + 25 × 2

= 84 cm² + 50 cm²

= 134 cm²