In Quadrilateral ABCD, BC is the diagonal, DO is perpendicular to BC, and CX is perpendicular to AB. If AB = 24cm, BC = 25cm, CX = 7cm and DO = 4cm, find the area of the quadrilateral
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[tex] { \small{ \sf \rightarrow \red{area(ABCD) = area(BCD) + area(ABC)}}}[/tex]
[tex] \small{ \rightarrow\sf area(ABCD) = (\frac{1}{2} \times BC \times OD) + ( \frac{1}{2} \times AB \times CX) }[/tex]
[tex] \small \sf \rightarrow area(ABCD) = (\frac{1}{2} \times 25 \times 4) + ( \frac{1}{2} \times 24 \times 7) [/tex]
[tex]\small \sf \rightarrow area(ABCD) = (50) + ( 84) [/tex]
[tex]\small \pink{ \sf \rightarrow area(ABCD) = 134 {cm}^{2} }[/tex]
[tex] \blue{ \bigstar \: \sf{Pre-Requisite \: Knowledge}}[/tex]
[tex] \small \green{\sf \: area \: of \triangle \: = \frac{1}{2} \times base \times height}[/tex]
[tex] \\ \\ \small{ \red {\bigstar}} \small{ \pmb{ \sf{ \fcolorbox{pink}{back}{ \: \:\: \:\: \: @Saanvigrover2007 \: \:\: \:\: \:}} \red \bigstar}} \\ [/tex]