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Ambrishi
@Ambrishi
May 2023
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. In order to prepare a 0.2M solution of sulphuric acid, how many gram of the acid must be dissolved in 250 ml water? [Ans. 4.9 gram]
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priya1sen
Verified answer
Answer:
4.9 gram of sulphuric acid
5 votes
Thanks 3
zarifmahmud763
W=SVM/1000
W = weight
S=molarity
M= molecular mass
V = volumes=250*0.2*98/1000
0 votes
Thanks 1
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Answers & Comments
Verified answer
Answer:
4.9 gram of sulphuric acid
W = weight
S=molarity
M= molecular mass
V = volumes=250*0.2*98/1000