1. mSM
mIT = mST + mSM
(1/2)(40) = 8 + mSM ---------------> diameter kasi kaya i half mo
20 = 8 +mSM
mSM = 20 - 8
mSM = 12 units
2. mSH
(mIT)^2 = (mSM)^2 + (mSH)^2
(mSH)^2 = 20^2 - 12^2
(mSH)^2 = 400 - 144
(mSH)^2 = 256
mSH =
mSH = 16 units
3. mCH
mIT = mST + mCH
40 = 8 + mCH
mCH = 40 - 8
mCH = 32 units
sana makatulong :)
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
1. mSM
mIT = mST + mSM
(1/2)(40) = 8 + mSM ---------------> diameter kasi kaya i half mo
20 = 8 +mSM
mSM = 20 - 8
mSM = 12 units
2. mSH
(mIT)^2 = (mSM)^2 + (mSH)^2
(mSH)^2 = 20^2 - 12^2
(mSH)^2 = 400 - 144
(mSH)^2 = 256
mSH =![\sqrt 256 \sqrt 256](https://tex.z-dn.net/?f=%5Csqrt%20256)
mSH = 16 units
3. mCH
mIT = mST + mCH
40 = 8 + mCH
mCH = 40 - 8
mCH = 32 units
sana makatulong :)