In how many ways can a MathSci Committee of five be formed from seven
Math lovers and five Science lovers if the committee must have three Math
lovers?
Math lovers and five Science lovers if the committee must have three Math
lovers?
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Answers & Comments
Answer:
350
Step-by-step explanation:
C(6,3) x C(4,2)
35 x 10
=350
5C2=5!/2!(5-2)/=5!/2!(3!)=(5)(4)(3)(2)(1)/(2)(1)(3)(2)(1)=(5)(2)/(1)=10
35×10=350