Answer:
Group of 5 men,which is n
Committee of 1 man,which is r
Using Formula of Combination
5C1=5!/4! 1!
5C1=5×4!/4! 1!,cancelled out 4!
5C1=5/1
5C1=5
Group of 4 women,which is n
Committee of 3 women,which is r
4C3=4!/1! 3!
4C3=4×3!/1! 3!,cancelled out 3!
4C3=4/1
4C3=4
=Committee of 1 man × Committee of 3 women
=5×4
=20 ways
:))))
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Answer:
Group of 5 men,which is n
Committee of 1 man,which is r
Using Formula of Combination
nCr=n!/(n-r)! r!
5C1=5!/(5-1)! 1!
5C1=5!/4! 1!
5C1=5×4!/4! 1!,cancelled out 4!
5C1=5/1
5C1=5
Group of 4 women,which is n
Committee of 3 women,which is r
Using Formula of Combination
nCr=n!/(n-r)! r!
4C3=4!/(4-3)! 3!
4C3=4!/1! 3!
4C3=4×3!/1! 3!,cancelled out 3!
4C3=4/1
4C3=4
=Committee of 1 man × Committee of 3 women
=5×4
=20 ways
:))))