in how many ways can 4 girls and 4 boys e seated in a row contai ning eight seats,
A. If they may seat any where?
B. If the boys and girls must sit
altern ately?
A. If they may seat any where?
B. If the boys and girls must sit
altern ately?
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Answer:
B. If the boys and girls must sit alternatetly
Answer:
A.1
B.40,320
Step-by-step explanation:
Permutation - arrangement does matter
Combination - arrangement doesn't matter
A.C(8, 8) (combination)
n! = 8! = 8! = 1 way
r!(n-r)! 8!(8-8) 8!(0)
B.P(8, 8)
n! = 8! = 8×7×6×5×4×3×2×1 = 40,320
(n-r) (8-8)! 0