Verified answer

Answer:

[tex]\huge\mathfrak{\underline{\underline{}{ANswEr}}}[/tex]

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From the the figure there is an external point X

XP=XQ [the length of the tangent drawn from an external point is equal]

SIMILARLY

AP=AR

BQ=BR

XP=XA+Ap___1

XQ=XB+BQ___2

BY SUBSTITUTING AP=AR and BQ=BR

XP=XA+AR

XQ=XB+BR

SINCE the tangents XP and XQ are equal, we get

XA+AR=XB+BR

Answer:

happy birthday dear rab tuhanu har khushi daa

aj mere sarya nu akhri mesh hai agar rab ne meri sun layi ta

because I am surfing from cancer antigen 125

prayer for me ma mar jawa plss