Answer:
"As AB = 3 cm and BC = 4 cm, AC = AB + BC = 3 + 4 = 7 cm.
Since ABC ∼ DEF, we can write the proportion:
AC/DE = AB/EF
7/4.5 = 3/EF
Cross multiplying and solving for EF, we get:
EF = (3 * 4.5) / 7 = 6.5 cm
So, the measure of EF is 6.5 cm, which is option (D).
The measure of side EF is 6 cm.
Given:
triangle ABC is similar to triangle DEF
AB = 3 cm
BC = 4 cm
DE = 4.5 cm
To Find:
we need to find the measure of the side EF
Solution:
we know that when two triangles are similar, the ratio of their corresponding sides is equal
as ABC ∼ DEF
⇒ AB/DE = BC/EF = CA/FD
substituting the values into the equation, we get-
3/4.5 = 4/EF
30/45 = 4/EF
EF = 4 × 45/30
EF = 4 × 3/2
EF = 2 × 3
EF = 6
Thus, the measure of side EF is 6 cm.
#SPJ3
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Answers & Comments
Answer:
"As AB = 3 cm and BC = 4 cm, AC = AB + BC = 3 + 4 = 7 cm.
Since ABC ∼ DEF, we can write the proportion:
AC/DE = AB/EF
7/4.5 = 3/EF
Cross multiplying and solving for EF, we get:
EF = (3 * 4.5) / 7 = 6.5 cm
So, the measure of EF is 6.5 cm, which is option (D).
The measure of side EF is 6 cm.
Given:
triangle ABC is similar to triangle DEF
AB = 3 cm
BC = 4 cm
DE = 4.5 cm
To Find:
we need to find the measure of the side EF
Solution:
we know that when two triangles are similar, the ratio of their corresponding sides is equal
as ABC ∼ DEF
⇒ AB/DE = BC/EF = CA/FD
substituting the values into the equation, we get-
3/4.5 = 4/EF
30/45 = 4/EF
EF = 4 × 45/30
EF = 4 × 3/2
EF = 2 × 3
EF = 6
Thus, the measure of side EF is 6 cm.
#SPJ3