Answer:
EF∣∣BC
By basic proportionality theorm ,
ΔAFE∼ΔABC
Similarly ,
ΔFBD∼ΔABC
ΔECD∼ΔACB
Att point D
∠BDF+∠FDE+∠EDC=180
60+∠FDE+60=180
∠FDE=60 ∘
Similarly,
∠DEF=∠DFE=60 ∘
Hence ΔDEF is equilateral triangle.
hope this will help u army
Step-by-step explanation:
ooh sleep on time
my study going nice
how is your study going on ??
Good night army
✌✌✌✌✌✌
hey army this drawing is made by me how is it?✌
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Verified answer
Answer:
EF∣∣BC
By basic proportionality theorm ,
ΔAFE∼ΔABC
Similarly ,
ΔFBD∼ΔABC
ΔECD∼ΔACB
Att point D
∠BDF+∠FDE+∠EDC=180
60+∠FDE+60=180
∠FDE=60 ∘
Similarly,
∠DEF=∠DFE=60 ∘
Hence ΔDEF is equilateral triangle.
hope this will help u army
Step-by-step explanation:
ooh sleep on time
my study going nice
how is your study going on ??
Good night army
✌✌✌✌✌✌
hey army this drawing is made by me how is it?✌
Answer:
EF∣∣BC
By basic proportionality theorm ,
ΔAFE∼ΔABC
Similarly ,
ΔFBD∼ΔABC
ΔECD∼ΔACB
Att point D
∠BDF+∠FDE+∠EDC=180
60+∠FDE+60=180
∠FDE=60 ∘
Similarly,
∠DEF=∠DFE=60 ∘
Hence ΔDEF is equilateral triangle.
Step-by-step explanation: