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Step-by-step explanation:

⦿ In Figure 6.14, lines $XY$ and $MN$ intersect at $O$. If $\angle POY = 90^\circ$ and $a:b = 2:3$, find $c$.

To find $c$, we need to use the information provided in the figure.

Since $\angle POY = 90^\circ$, this means that triangle $POY$ is a right triangle.

In a right triangle, we can use the Pythagorean theorem to find the lengths of the sides.

Let $a$ be the length of $PX$, and $b$ be the length of $PY$.

Since $a:b = 2:3$, we can let $a = 2x$ and $b = 3x$, where $x$ is a common factor.

According to the Pythagorean theorem, we have:

[tex]\sf{OP^2 = PX^2 + OY^2}[/tex]

or, $c^2 = (2x)^2 + (3x)^2$

or, $c^2 = 4x^2 + 9x^2$

or, $c^2 = 13x^2$

Simplifying, we get:

$c^2 = 13x^2$

Taking the square root of both sides, we get:

$c = \sqrt{13x^2}$

Therefore, $c$ is equal to the square root of $13$ times $x$.

Answer:

Hari bought oranges at rupees 10 a dozen and bananas at rupees 4.50 a dozen. If he paid rupees 34 for these fruits of which oranges were 2.5 dozen, how many dozen of Bananas did

Step-by-step explanation: