Given :

Total distance = d = 30 km

Ajay takes 2 hours more than sameer

Ajay doubles his speed,then he would take 1hr less than sameer

To Find :

The speed of Ajay

Solution :

Let The speed of Sameer = s km/h

The speed of Ajay = a km/h

Let the time taken by Sameer = x hours

Let The time taken by Ajay = y hours

Statement I

∵  Time taken by Ajay = 2 + time taken by Samer

i.e      y = 2 + x

∵  speed =

For Ajay

    a =

Or,   a =              .........1

For Sameer

     s =

Statement II

Ajay doubles his speed,then he would take 1hr less than sameer

For Ajay

     a =

Or,  2 a =              .........2

For Sameer

     s =

Solving eq 1 and eq 2

i.e   2 ×  =  

or,    =  

Or,  2 ( x - 1 ) = 2 + x

Or,  2 x - 2 = 2 + x

Or,  2 x - x = 2 + 2

Or,          x = 4 hours

i,e Time taken by Sameer = x = 4 hours

Now, Put the value of x into eq 2

So, 2 a =  

Or,  2 a =

Or,  2 a =

∴     2 a = 10

Or,     a = = 5 km/h

i.e   Speed of Ajay = a = 5 km/h

Hence, The Speed of Ajay in covering 30 km distance is 5 km/h   Answer