Answer:

a25 = 127

to solve the 25th term:

Given:

a5 = 27

a10 = 52

n = 25

to find r

d = √(a10 - a5)

d = √(52 - 27)

d = 5

to find a1 using the general formula

a5 (given) = a1+(n-1)d

27 = a1+(5-1)5

27 = a1+(4)5

27 = a1+20

27-20 = a1+20-20

7 = a1

to find the 25th term

the general formula for Arithmetic Sequence:

an = a1+(n-1)d

a25 = 7+(25-1)5

a25 = 7+(24)5

a25 = 7+120

a25 = 127

The 25th term is 127 :D