In ∆ABC, AB = AC = x; BC = 10 cm and the area of the triangle is 60 cm^2. Find x.
Answers & Comments
Arinkishore
Hey Prince, consult this picture for the diagram Continuation of Ans:-
h=12cm As,it is an iso.∆.....So the perpendicular divides the triangle into half In∆AMC AC^2=AM^2+MC^2 x^2=12^2+5^2 x^2=144+25=169 x=√169 13 cm....Answer
Answers & Comments
consult this picture for the diagram
Continuation of Ans:-
h=12cm
As,it is an iso.∆.....So the perpendicular divides the triangle into half
In∆AMC
AC^2=AM^2+MC^2
x^2=12^2+5^2
x^2=144+25=169
x=√169
13 cm....Answer