In ∆ ABC , AB=AC and D is the mid point of BC (1) State the 3 pairs of equal parts in ∆ADB and ∆ADC (2) Name the two triangles that are congruent in symbolic form (write the congruence used)
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Answer:
1 ) In triangle ABC
AB = AC ( Given )
AD = AD ( Common Line )
angle B = angle C ( Opposite angles )
2 )∆ADB ≈∆ADC (SIDE ANGLE SIDE )
Answer:
in triangle ABD and ACD
AB=AC(given)
BD=CD( D is mid point of BC )
AD=AD(common)
therefore ABD=~ ACD(by sss)