In a triangle ABC, one of the angles is 50 % more than the sum of the other two angles. Find the largest angle.
Answers & Comments
Bubu11
X+y+z =180° x+y+{150/100×(x+y)}=180° x+y(1+150/100)=180° x+y(100+150)/100=180 x+y=180×100/250=72° so the largest angle is 180-72=108° or the largest angle is 72 ×150/100=108°
Answers & Comments
x+y+{150/100×(x+y)}=180°
x+y(1+150/100)=180°
x+y(100+150)/100=180
x+y=180×100/250=72°
so the largest angle is 180-72=108°
or
the largest angle is 72 ×150/100=108°