Answer:

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Explanation:

Solution

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The reaction taking place at anode is:

71.0 g

2Cl

−

→

1 mole

71.0 g

Cl

2

+

2×96500 coulomb

2e

−

Q=I×t=100×5×60×60 coulomb

The amount of chlorine liberated by passing 100×5×60×60 coulomb of electric charge

=

2×9500

1

×100×5×60×60=9.3264 mole

Volume of Cl

2

liberated at NTP=9.3264×22.4=208.01 L.

Answer:

14.4 A

Explanation:

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