Answer:
I Hope Sum is Correct
Step-by-step explanation:
Take The Sum As Common And Have The Supplinentry 180 applied :D
∠A:∠D=3:7
Let ∠A and ∠D be 3x and 7x.
⇒ ∠B:∠C=9:6
Let ∠A and ∠D be 9y and 6y.
Since, AB∥CD and AD is a transversal.
∴ ∠A+∠D=180o. [ Interior angles on same side of transversal ]
⇒ 3x+7x=180o.
⇒ 10x=180o.
⇒ x=18o
⇒ ∠A=3×18o=54o
⇒ ∠D=7×18o=126o.
Since, AB∥CD and BC is a transversal.
∴ ∠B+∠C=180o. [ Interior angles on same side of transversal ]
⇒ 9y+6y=180o
⇒ 15y=180o
∴ y=12o
⇒ ∠B=9×12o=108o
=> ∠C=6×12o=72o
Here o is degree.
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Answers & Comments
Answer:
I Hope Sum is Correct
Step-by-step explanation:
Take The Sum As Common And Have The Supplinentry 180 applied :D
Verified answer
Step-by-step explanation:
∠A:∠D=3:7
Let ∠A and ∠D be 3x and 7x.
⇒ ∠B:∠C=9:6
Let ∠A and ∠D be 9y and 6y.
Since, AB∥CD and AD is a transversal.
∴ ∠A+∠D=180o. [ Interior angles on same side of transversal ]
⇒ 3x+7x=180o.
⇒ 10x=180o.
⇒ x=18o
⇒ ∠A=3×18o=54o
⇒ ∠D=7×18o=126o.
Since, AB∥CD and BC is a transversal.
∴ ∠B+∠C=180o. [ Interior angles on same side of transversal ]
⇒ 9y+6y=180o
⇒ 15y=180o
∴ y=12o
⇒ ∠B=9×12o=108o
=> ∠C=6×12o=72o
Here o is degree.
Hope this answer is helpful to you.
Please mark me as Brilliant...