In a game of chance there is spinning of an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and there are equally likely outcomes. What is the probability that it will point at 7? *
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Answer:
Given that,
Number of events =1,2,3,4,5,6,7,8
Total numbers n(S)=8
Factor of 8=1,2,4 and 8
Number of factor n(E)=4
Therefore,
Probability=
n(S)
n(E)
=
8
4
Probability=
2
1
.